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Math Help - Domain, range, and asymptotes - is this correct?

  1. #1
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    Domain, range, and asymptotes - is this correct?

    Is this correct?

    y = 1 / (x^2 + 12x - 13)
    Domain:all > 1 and < 2
    Range: all < -1
    Horizontal: none
    Vertical: x=1, x=2
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  2. #2
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    Quote Originally Posted by olen12 View Post
    Is this correct?

    y = 1 / (x^2 + 12x - 13)
    Domain:all > 1 and < 2
    Range: all < -1
    Horizontal: none
    Vertical: x=1, x=2
     y=\frac{1}{x^2 + 12x - 13}

     y=\frac{1}{(x+13)(x-1)}

    Vertical Asymptote x = -13, and x =1

    Horizontal Asymptote y=0 (x-axis)

    Domain = \{x \in \mathbb{R} \;|\; x \ne -13, 1\}

    Range = \{y \in \mathbb{R} \;|\; y \ne 0\}
    Last edited by Shyam; April 17th 2009 at 06:32 PM.
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  3. #3
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    Quote Originally Posted by olen12 View Post
    Is this correct?
    How did you obtain your answers?

    . . . . .Google results for "domain rational functions"

    . . . . .Google results for "asymptotes"

    . . . . .Google results for "how to find range function"

    . . . . .Google results for "graphing rational functions"

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