Is this correct?
y = 1 / (x^2 + 12x - 13)
Domain:all > 1 and < 2
Range: all < -1
Horizontal: none
Vertical: x=1, x=2
$\displaystyle y=\frac{1}{x^2 + 12x - 13}$
$\displaystyle y=\frac{1}{(x+13)(x-1)}$
Vertical Asymptote x = -13, and x =1
Horizontal Asymptote y=0 (x-axis)
Domain = $\displaystyle \{x \in \mathbb{R} \;|\; x \ne -13, 1\}$
Range = $\displaystyle \{y \in \mathbb{R} \;|\; y \ne 0\}$
How did you obtain your answers?
. . . . .Google results for "domain rational functions"
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. . . . .Google results for "graphing rational functions"