1. Alegbra

SOLVE FOR number 1.
If
2^3 = (0*3^2) + (3*2) + 2 = 8
3^3 = (1*4^2) + (3*3) + 2 = 27
4^3 = (2*5^2) + (3*4) + 2 = 64
then
1.) n^3 = (n-2) * ( )^2) + (3 * )+ 2 = n^3

2. Originally Posted by Crystal09
SOLVE FOR number 1.
If
2^3 = (0*3^2) + (3*2) + 2 = 8
3^3 = (1*4^2) + (3*3) + 2 = 27
4^3 = (2*5^2) + (3*4) + 2 = 64
then
1.) n^3 = (n-2) * ( )^2) + (3 * )+ 2 = n^3
$n^3 = (n-2)(n+1)^2 + 3n + 2$