My problem is that i don't know how to multiply parentheses such as
(x-4)(x+2)(4/2) or (6/5)(5)(w-3). Is there any specific rule regarding this?
A rule of thumb is that every term in a paraenthesis should be multiplied with every term in another.
For ex $\displaystyle (x-2)(x-3) $
Begin with the x in the first parenthesis, multiply this with the x in the second paraenthesis then the -3. Then do the same thing for the -2 in the first.
$\displaystyle (x-2)(x-3) = x^2 -3x -2x +6 $
Order of operations - Wikipedia, the free encyclopedia
I will do one for you
(x+4)(x+2)(4/2)
(4/2)= (2)
(x+4)(x+2)(2)
(x+4) ( (2)x +(2)(2) )
(x+4)(2x +4)
(x(2x+4) + 4(2x+4) )
((x*2x + x*4) + (4*2x + 4*4))
(2x^2 + 4x + 8x +16)
(2x^2 + 12x + 16)
Now try and tell me the answer of second.