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Math Help - Another Inequality...

  1. #1
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    Another Inequality...

    28(pi^3)/24x^2<.00001

    I honestly don't really know where to go with this one again, I've tried it a couple of times and just end up stuck in different places.
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by fattydq View Post
    28(pi^3)/24x^2<.00001

    I honestly don't really know where to go with this one again, I've tried it a couple of times and just end up stuck in different places.
    i suppose you mean \frac {28 \pi^3}{24}x^2 < 0.00001

    divide both sides by \frac {28 \pi^3}{24}, then square root both sides, you will get two answers. plot them on a number line, and test all the intervals to see which are correct
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  3. #3
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    e^(i*pi)'s Avatar
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    This is pretty much the same problem I posted in your other thread, just replace the 12 in that thread with 24

    http://www.mathhelpforum.com/math-he...nequality.html
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  4. #4
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    Quote Originally Posted by Jhevon View Post
    i suppose you mean \frac {28 \pi^3}{24}x^2 < 0.00001

    divide both sides by \frac {28 \pi^3}{24}, then square root both sides, you will get two answers. plot them on a number line, and test all the intervals to see which are correct
    No I mean 28(pi^3)/(24x^2)<.00001
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  5. #5
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    I actually tried that, to be honest I can't really make sense of your work and was hoping someone could explain it step by step. I'm still replying in that thread if you care to try to help me further...
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  6. #6
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by e^(i*pi) View Post
    This is pretty much the same problem I posted in your other thread, just replace the 12 in that thread with 24

    http://www.mathhelpforum.com/math-he...nequality.html
    well, in that case: thread closed.

    Quote Originally Posted by fattydq View Post
    I actually tried that, to be honest I can't really make sense of your work and was hoping someone could explain it step by step. I'm still replying in that thread if you care to try to help me further...
    tsk tsk, fattydq! it is not very polite to go behind someone's back when they tried to help you and seek answers elsewhere. just ask them to clarify and do not make a new thread.
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