# Math Help - Another Inequality...

1. ## Another Inequality...

28(pi^3)/24x^2<.00001

I honestly don't really know where to go with this one again, I've tried it a couple of times and just end up stuck in different places.

2. Originally Posted by fattydq
28(pi^3)/24x^2<.00001

I honestly don't really know where to go with this one again, I've tried it a couple of times and just end up stuck in different places.
i suppose you mean $\frac {28 \pi^3}{24}x^2 < 0.00001$

divide both sides by $\frac {28 \pi^3}{24}$, then square root both sides, you will get two answers. plot them on a number line, and test all the intervals to see which are correct

3. This is pretty much the same problem I posted in your other thread, just replace the 12 in that thread with 24

http://www.mathhelpforum.com/math-he...nequality.html

4. Originally Posted by Jhevon
i suppose you mean $\frac {28 \pi^3}{24}x^2 < 0.00001$

divide both sides by $\frac {28 \pi^3}{24}$, then square root both sides, you will get two answers. plot them on a number line, and test all the intervals to see which are correct
No I mean 28(pi^3)/(24x^2)<.00001

5. I actually tried that, to be honest I can't really make sense of your work and was hoping someone could explain it step by step. I'm still replying in that thread if you care to try to help me further...

6. Originally Posted by e^(i*pi)
This is pretty much the same problem I posted in your other thread, just replace the 12 in that thread with 24

http://www.mathhelpforum.com/math-he...nequality.html
well, in that case: thread closed.

Originally Posted by fattydq
I actually tried that, to be honest I can't really make sense of your work and was hoping someone could explain it step by step. I'm still replying in that thread if you care to try to help me further...
tsk tsk, fattydq! it is not very polite to go behind someone's back when they tried to help you and seek answers elsewhere. just ask them to clarify and do not make a new thread.