Let the length of the pasture be L, and th width w. So wL = 8750.

Now draw yourself a picture. Let the width of th larger sub-pasture be s. Then 2.5s = L.

Also, in the smaller sub-pasture we have s+2L=190.

So we have three variables and three equations:

wL = 8750

2.5s = L

s+2L = 190

You will see that you can use the last two equations to find s and L, and then you can find w:

2.5s = L so:

s + 2L = s + 2(2.5L) = 6s = 190

s = 190/6

L = 2.5s = 2.5(190/6)

Finally:

wL = 8750

w = 8750/L etc. you can finish it off.

The numbers look a bit odd to me, so please check I haven't made any silly mistakes.

The second question can be done similarly; try it yourself, and ask if you get stuck.