Fractions in a probablity problem?

**Verranicus** · April 15th 2009, 12:16 PM

So, I've been doing problems on probablity. Stuff like:

12 over 9 = x over 7, solving for x.

But I just got to a question that was this:

2/7 over 3/4 = 5/6 over x

I have NO idea how to even begin. Help? D:

**Showcase_22** · April 15th 2009, 02:17 PM

$\frac{\frac{2}{7}}{\frac{3}{4}}=\frac{\frac{5}{6}} {x}$

$\frac{2}{7}x=\frac{15}{24}$

...and I think you can take it from here.

**e^(i*pi)** · April 15th 2009, 02:22 PM

Originally Posted by Showcase_22

$\frac{\frac{2}{7}}{\frac{3}{4}}=\frac{\frac{5}{6}} {x}$

$\frac{2}{7}x=\frac{15}{24}$

...and I think you can take it from here.

$\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a}{b} \times \frac{d}{c}$

For your example do what the guy above said

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