# Thread: Partial Fractions Again =p

1. ## Partial Fractions Again =p

Hey guys

For the partial fraction:

$\frac{2x^2 + x + 6}{x^2 -4}$

How exactly does it become:

$2 + \frac{4}{x-2} - \frac{3}{x+2}$

I have no clue how the "2" appears.

Thanx a lot!

2. Originally Posted by xwrathbringerx
Hey guys

For the partial fraction:

$\frac{2x^2 + x + 6}{x^2 -4}$

How exactly does it become:

$2 + \frac{4}{x-2} - \frac{3}{x+2}$

I have no clue how the "2" appears.

Thanx a lot!
Long division gives

$\frac{2x^2 + x + 6}{x^2 - 4} = 2 + \frac{x + 14}{x^2 - 4}$.

Now use Partial Fractions on the $\frac{x + 14}{x^2 - 4}$.