Hey guys For the partial fraction: $\displaystyle \frac{2x^2 + x + 6}{x^2 -4}$ How exactly does it become: $\displaystyle 2 + \frac{4}{x-2} - \frac{3}{x+2}$ I have no clue how the "2" appears. Please help? Thanx a lot!
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Originally Posted by xwrathbringerx Hey guys For the partial fraction: $\displaystyle \frac{2x^2 + x + 6}{x^2 -4}$ How exactly does it become: $\displaystyle 2 + \frac{4}{x-2} - \frac{3}{x+2}$ I have no clue how the "2" appears. Please help? Thanx a lot! Long division gives $\displaystyle \frac{2x^2 + x + 6}{x^2 - 4} = 2 + \frac{x + 14}{x^2 - 4}$. Now use Partial Fractions on the $\displaystyle \frac{x + 14}{x^2 - 4}$.
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