# Partial Fractions Again =p

• April 15th 2009, 06:36 AM
xwrathbringerx
Partial Fractions Again =p
Hey guys

For the partial fraction:

$\frac{2x^2 + x + 6}{x^2 -4}$

How exactly does it become:

$2 + \frac{4}{x-2} - \frac{3}{x+2}$

I have no clue how the "2" appears.

Thanx a lot!
• April 15th 2009, 07:26 AM
Prove It
Quote:

Originally Posted by xwrathbringerx
Hey guys

For the partial fraction:

$\frac{2x^2 + x + 6}{x^2 -4}$

How exactly does it become:

$2 + \frac{4}{x-2} - \frac{3}{x+2}$

I have no clue how the "2" appears.

$\frac{2x^2 + x + 6}{x^2 - 4} = 2 + \frac{x + 14}{x^2 - 4}$.
Now use Partial Fractions on the $\frac{x + 14}{x^2 - 4}$.