Shouldn't the second numerator be of the form "Bx + C", due to the fact that the denominator is of degree 2...?
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How do i solve this partial fraction:
I tried using the same method as I did before...
Let x = -1
4+2 = 2A
6 = 2A
A = 3
Differentiate both sides.
8x - 2 = 2Ax + B
Substitute in A = 3
8x - 2 = 6x + B
2x-2 = B
I keep on getting 2x - 2 as the value for B even though it's meant to be x - 3.
Could someone please point out what i did wrong?