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Math Help - simplifying radicals and fractional indices

  1. #1
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    simplifying radicals and fractional indices

    Hi there

    First post here. I hope you can help!

    I have a complete block on simplifying the following -

    (x-1).√(x+1) (x-1)^1.5

    I have the answer but I just can't see the method to get there. I would appreciate if someone can work through it for me.

    Thanks in advance for any help

    Cheers
    Last edited by salamander; April 15th 2009 at 04:05 AM.
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  2. #2
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    I am uncertain whether I got the polynomial, but if I did so, I believe simplication is as follows:

    Does not appear to be very simple, but I can't do better.

    Perhaps you could provide the answer?
    Attached Thumbnails Attached Thumbnails simplifying radicals and fractional indices-f.gif  
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  3. #3
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    Hi logic!

    Thanks for your reply... looks like i made an error there in my formula... i have edited it above.

    Sorry about that... I will add the answer when i next get home

    Thanks again.....
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  4. #4
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    Quote Originally Posted by salamander View Post
    Hi logic!

    Thanks for your reply... looks like i made an error there in my formula... i have edited it above.

    Sorry about that... I will add the answer when i next get home

    Thanks again.....
    (x-1).√(x+1) (x-1)^1.5

    Use the difference of two squares for x^2-1

    (x^2-1)^2 = (x-1)^2(x+1)^2

    This gives us

    \frac{(x-1)^2(x+1)^2(x+1)^{0.5}}{(x-1)^{1.5}}

     = (x+1)^{2+0.5}(x-1)^{2-1.5}
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  5. #5
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    Thanks e but that does not match the solution I have.

    Here I will see if I can use the nifty Maths code and rewrite the question and solution.....

    Q. Simplify the following giving result without fractional indices

    \frac{(x^2-1)^2(x+1)^{0.5}}{(x-1)^{1.5}}

    A. and the solution is

    (x+1)^2(x^2-1)^{0.5}

    (to be true to the question you would use the radical in place of the fractional exponent... how do you do this with maths code?)

    This question has really got me stumped.
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  6. #6
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    This looks fine.
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  7. #7
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    Got it sussed now thanks for your help
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