please see the file attachedfor the question
thanks
This matrix is equivalent to this system:
$\displaystyle x + 3z = b$
$\displaystyle y = -2$
$\displaystyle az = 8$
The first question asks to set $\displaystyle a = 2$ and $\displaystyle b = 3$.
That is, solve:
$\displaystyle x + 3z = 3$
$\displaystyle y = -2$
$\displaystyle 2z = 8$
The third equation tells us that $\displaystyle z = 4$. Substituting this result into the first equation, we get $\displaystyle x + 12 = 3$. So $\displaystyle x = -9$.
That's all. For part (a), the answer is that $\displaystyle x = -9$, $\displaystyle y = -2$, and $\displaystyle z = 4$.
Just do exactly the same steps to solve part (b).