1. ## factorizing question

how do you factorize this question: 49-(x+1)^2

i would have known how to do it, if the 49 was on the other side: (x+1)^2 - 49
then you would just find the square root of 49 which is 7
and make (x+1+7)(x+1-7) and simplify.
but i don't know how to do it with the 49 on the other side.

Thanks for the help sorry its an easy question lol this is still advanced for me

2. As long as it is subtraction, there is little concern where the constant should stand. You would the exactly the same and get:
49-(x+1)^2 = (7-(x+1))*(7+(x+1))

Be careful not to miss a bracket:
(7-(x+1)) does not equal (7-x+1).

3. so how do you simplify this: (7-(x+1))*(7+(x+1))

4. (7-(x+1))*(7+(x+1))

You could get rid of the internal brackets:
(7-(x+1))*(7+(x+1)) = (7-x-1)(7+x+1)=(6-x)(x+8)=-(x-6)(x+8).
You could get rid of these brackets aswell, but it cannot get simpler than that.

5. The easiest way might be to take the negative sign outside...

49-(x+1)^2 = -[(x+1)^2 -49]=-[(x+8)(x-6)]=(x+8)(6-x)

In the last step take the negative to one of the factors.