As long as it is subtraction, there is little concern where the constant should stand. You would the exactly the same and get:
49-(x+1)^2 = (7-(x+1))*(7+(x+1))
Be careful not to miss a bracket:
(7-(x+1)) does not equal (7-x+1).
how do you factorize this question: 49-(x+1)^2
i would have known how to do it, if the 49 was on the other side: (x+1)^2 - 49
then you would just find the square root of 49 which is 7
and make (x+1+7)(x+1-7) and simplify.
but i don't know how to do it with the 49 on the other side.
Thanks for the help sorry its an easy question lol this is still advanced for me