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Math Help - Stuck on a square root problem

  1. #1
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    Post Stuck on a square root problem

    Hi! I am stuck on my homework. I came across a problem I didn't know how to do and there isn't a single example like it in my book or notes. The problem is-

    Find where the square root of x-3 over -2x-8 is real

    Thanks for your help!
    Ashley
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  2. #2
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    Quote Originally Posted by aperkin2 View Post
    Hi! I am stuck on my homework. I came across a problem I didn't know how to do and there isn't a single example like it in my book or notes. The problem is-

    Find where the square root of x-3 over -2x-8 is real

    Thanks for your help!
    Ashley
    Hi

    \sqrt{\frac{x-3}{-2x-8}} is real when \frac{x-3}{-2x-8} \geq 0 which means

    ( x-3 \geq 0 and -2x-8 > 0) or ( x-3 \leq 0 and -2x-8 < 0)
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  3. #3
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    Thank you so much for your help! That is starting to sound a little more familiar. Would the next step involve a number line or is there another step before that? Sorry, I'm just very lost here. Thanks for your help!
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  4. #4
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    You just need to find :
    - the set of x where x-3 \geq 0 and -2x-8 > 0
    - the set of x where x-3 \leq 0 and -2x-8 < 0

    And take the union of both sets. This is the answer you are asked
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  5. #5
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    Oh I see! Thank you so much! I never would have figured that out on my own
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