Thread: Imaginary Numbers

Having trouble with the following problem:

(2 + 2i) (3 - 4i)

I have worked out this much so far.

6 - 8i + 6i - 8i^2

6 - 2i - 8i^2

Since there is an "i" squared, do i distribute that with the preceding "8" coefficient?

Also running into a problem solving the following word problem:

"The sum of the squares of two consecutive positive odd integers is 514. What are the integers?"

I have it set up as x^2 + (x+2)^2 = 514

x^2 + x^2 + 4x + 4 = 514

2x^2 + 4x = 510

Thanks again for everyone's help!

Originally Posted by Hapa

Since there is an "i" squared, do i distribute that with the preceding "8" coefficient?

By definition, Substitute this into your expression.

"The sum of the squares of two consecutive positive odd integers is 514. What are the integers?"

I have it set up as x^2 + (x+2)^2 = 514

x^2 + x^2 + 4x + 4 = 514

2x^2 + 4x = 510

You should be able to factor this:





Can you break -255 into two factors whose sum is 2? Start by listing the possible factorizations of -255:









Now which pair adds up to +2?