Having trouble with the following problem:

(2 + 2i) (3 - 4i)

I have worked out this much so far.

6 - 8i + 6i - 8i^2

6 - 2i - 8i^2

Since there is an "i" squared, do i distribute that with the preceding "8" coefficient?

Also running into a problem solving the following word problem:

"The sum of the squares of two consecutive positive odd integers is 514. What are the integers?"

I have it set up as x^2 + (x+2)^2 = 514

x^2 + x^2 + 4x + 4 = 514

2x^2 + 4x = 510

Thanks again for everyone's help!