1 + 4i / 1 - i

Thanks in advance!

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- Apr 12th 2009, 04:07 PMHapaPerform indicated operation (simplify as a+bi)
1 + 4i / 1 - i

Thanks in advance! - Apr 12th 2009, 04:23 PMmr fantastic
- Apr 12th 2009, 04:26 PMHapa
My apologies. Yes, it is as you listed

(1 + 4i) / (1 - i) - Apr 12th 2009, 04:28 PMe^(i*pi)
Use the difference of two squares $\displaystyle a^2-b^2 = (a-b)(a+b)$

and $\displaystyle i^2 = -1$ to rationalise the denominator

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