from the linear example so far I have...

Profit = 20X + 16Y

and the constraints are:

X + 2Y ≤ 480

3X + 4Y≤1080

How do I show theFeasible Regionand theOptimal Pointon a graph.??

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- April 12th 2009, 08:30 AMbobchibaGraphing a feasible Region?
from the linear example so far I have...

**Profit = 20X + 16Y**

and the constraints are:

**X + 2Y ≤ 480**

**3X + 4Y≤1080**

How do I show the**Feasible Region**and the**Optimal Point**on a graph.?? - April 12th 2009, 09:35 AMmasters
Hello bobchiba,

I'm assuming that and .

Graph the two equalities:

and

Shade the appropriate regions indicated by the inequalities and find where they overlap. This is your feasible region.

Three of the vertices lie on the axes: (0, 0), (360, 0) , and (0, 240).

To find the 4th vertex, solve the two linear equations for their intersection point.

See attachment.

Then to find your optimal point or wher the profit function produces the largest value, substitute each vertex coordinates into your function and see what comes out. - April 15th 2009, 05:01 AMbobchiba
Sorry I left out some of the constraints, they are all as follows:

X + 2Y 480

3X + 4Y 1080

X 60

Y 30 - April 15th 2009, 05:30 AMstapel
Do you have a question regarding the graph and instructions you've been provided? Thank you! :D

- April 15th 2009, 05:50 AMbobchiba
yes I sort of get what masters originally provided, but I forgot to mention that x and Y are not equal to zero, and its

X http://www.mathhelpforum.com/math-he...892dad38-1.gif 60

Yhttp://www.mathhelpforum.com/math-he...892dad38-1.gif 30 - April 15th 2009, 06:21 AMstapel
Okay; then follow the exact same graphing, corner-finding, and evaluating process outlined, but using your inequalities instead of the standard ones guessed in that earlier reply. (Wink)

If you get stuck, please reply showing (or describing) your work and reasoning, clearly stating where you are having difficulty. Thank you! :D - April 15th 2009, 06:33 AMmasters