The remainder obtained when the polynomial x+x^3 +x^9+x^27+x^81+x^2^243 is divided by x^2-1 is:
The answer is given as 6x but I dont know how to proceed.
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Shouldn't it be: ?
Anyway, when divided by : , where Q(x) is the quotient, R(x) is the remainder. Its degree can be at most 1, so and
Now you've got 2 simultaneous equations, solving for a and b gives a=6, b=0 so R(x)=6x.
nopes . x^2^243 only
anyways, will try with your method and c if i can get an answer.
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