i'm working pre-algebra on my own so i can take pre-calc and then calc. I am going to post whenever i run into problems. heres one from chap 4, Sec 4.5.

The book graphs the p intercept as 0 but i get 300. heres the problem.

15. Graph each formula for the given values of the independent variable.

P = 40n + 300, 0 ≤ n ≤ 200

i get the ordered pair as ( n, P ),

the slope as 40n,

and the P int as ( 0, 300)

this concludes me to graph the Y or P int at 300, but the answer at the back of the book graphs at 0 w/ the slope being 40/1. Can someone explain why the P int is at 0 and not at 300.