# Thread: simple question ... just can't figure it out

1. ## simple question ... just can't figure it out

Solove for y:

y^(2/3) = 2 - y^4

SHOW THE STEPS PLZ

2. Why do you believe it can be solved?

What methods have you for your attempt?

What have you tried?

Just looking at it, I think I'd try y = 1 and y = -1.

3. Originally Posted by lidstrompl
Solove for y:

y^(2/3) = 2 - y^4
Let x = y^(1/3), so y^(2/3) = x^2 and y^4 = y^(12/3) = x^12.

Substituting, you should get x = 2 - x^12, so you are trying to find the solutions of x^12 + x^2 - 2 = 0, which are the x-intercepts of f = x^12 + x^2 - 2.

Plug x^12 + x^2 - 2 into your graphing calculator to "see" where the two real-values zeroes are. Divide out the two rational zeros (which duplicate the two rational zeroes of the original equation).

You should be left with an equation in x^10 which has no real zeroes.

4. Originally Posted by TKHunny
Why do you believe it can be solved?

What methods have you for your attempt?

What have you tried?

Just looking at it, I think I'd try x = 1 and x = -1.

ye, just noticed that as well. Just didn't want to get messy with unnecessary algebra. 1 and -1 in the solution is actually all i need for my problem. Thanks.