Solve:
x^3 + 6x = 4x^2
Follow the standard process: Move everything over to one side of the "equals" sign, take the common factor out front, and then apply the Quadratic Formula to solve the remaining quadratic factor.
If you get stuck, please reply showing how far you have gotten. Thank you!
x^3 + 6x = 4x^2
x^3 - 4x^2 + 6x = 0
x(x^2 - 4x + 6) = 0
x= (-(-4)±√((-4)^2 -4(1)(6)))/2
x= (4±√(16 -24))/2
x= (4±√-8)/2
What did I do wrong? I can't take the square root of a negative number. And we haven't gone through imaginary numbers yet so I don't think we would you those to solve the above.