Any help would be greatly appreciated. Thanks.

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- Apr 9th 2009, 05:17 AM #1

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- Apr 9th 2009, 06:01 AM #2

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- Apr 9th 2009, 06:18 AM #3

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- Apr 9th 2009, 06:22 AM #4

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- Apr 9th 2009, 07:23 AM #5

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Your images are somewhat huge, so I'll repost the exercises here, along with my guesses as to what the instructions had been.

$\displaystyle \mbox{1) Simplify: }\, \frac{\left(10x^{-2}\right)(y^3)(5^{-1})\left(\frac{1}{y}\right)}{\left(\frac{1}{x^2}\r ight)\left(2\right)\left(\frac{1}{y^4}\right)}$**here**. To learn how to simplify expressions such as the above, try**here**.

To get you started:

. . . . .$\displaystyle \frac{\left(\frac{10}{x^2}\right)\left(\frac{y^3}{ 1}\right)\left(\frac{1}{5}\right)\left(\frac{1}{y^ 1}\right)}{\left(\frac{1}{x^2}\right)\left(\frac{2 }{1}\right)\left(\frac{1}{y^4}\right)}\, =\, \frac{\left(\frac{10\times y^3\times 1 \times 1}{x^2\times 1\times 5\times y}\right)}{\left(\frac{1\times 2\times 1}{x^2 \times 1\times y^4}\right)}\, =\, \left(\frac{10y^3}{5x^2 y}\right)\, \times\, \left(\frac{x^2 y^4}{2}\right)$

$\displaystyle \mbox{2) Combine into one term: }\, \log(20b^3)\, -\,\log(5^2 b^2)\, +\, log(35)\, -\, log(28)$**here**.

To get you started:

. . . . .$\displaystyle \log(20b^3)\, -\,\log(5^2 b^2)\, +\, log(35)\, -\, log(28)$

. . . . .$\displaystyle =\, \log(20b^3)\, +\, \log(35)\, -\, \left(\log(5^2 b^2)\, +\, \log(28)\right)$

. . . . .$\displaystyle =\, \log\left(20b^3\, \times\, 35\right)\, -\, \log\left(5^2 b^2\, \times \, 28\right)$

$\displaystyle \mbox{3) Given }\, P(x)\, =\, 5x^3\, -\,4x^2\, +\,2x \, -\, 1\, \mbox{ and }\, D(x)\, =\, x\, -\, 2,$

$\displaystyle \mbox{find the product }\, \left(P(x)\right)\left(D(x)\right).$**here**.

Once you have learned the basic terms and techniques, please attempt the exercises. If you get stuck, you will then be able to reply with a clear listing of your work and reasoning so far, so we can "see" where you're stuck and then provide intelligent assistance.

Thank you!

- Apr 9th 2009, 09:19 AM #6

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