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Math Help - I need help

  1. #1
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    I need help






    Any help would be greatly appreciated. Thanks.
    Last edited by xflex; April 9th 2009 at 05:30 AM.
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  2. #2
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    Hi

    \frac{10\:x^{-2}:y^3\cdot\:5^{-1}\:\frac{1}{y}}{\frac{1}{x^2}\:2\:\frac{1}{y^4}} = \frac{10}{x^2}\:\frac{1}{y^3}\:\frac{1}{5}\:\frac{  1}{y}\:x^2\:\frac{1}{2}\:y^4 = 1
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  3. #3
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    Quote Originally Posted by running-gag View Post
    Hi

    \frac{10\:x^{-2}:y^3\cdot\:5^{-1}\:\frac{1}{y}}{\frac{1}{x^2}\:2\:\frac{1}{y^4}} = \frac{10}{x^2}\:\frac{1}{y^3}\:\frac{1}{5}\:\frac{  1}{y}\:x^2\:\frac{1}{2}\:y^4 = 1
    Should it be y^6 instead of 1? (I'm assuming the semi-colon as a typo for multiplication)

    For Q2,

    use this rule:
    log (a) + log (b) = log (a*b)
    log (a) - log (b) = log (a/b)

    And you will transform the line into a fraction to simplify.
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  4. #4
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    Quote Originally Posted by knighty View Post
    Should it be y^6 instead of 1? (I'm assuming the semi-colon as a typo for multiplication)
    You may be right
    I assumed ":" was a division
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  5. #5
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    Talking

    Your images are somewhat huge, so I'll repost the exercises here, along with my guesses as to what the instructions had been.

    \mbox{1) Simplify: }\, \frac{\left(10x^{-2}\right)(y^3)(5^{-1})\left(\frac{1}{y}\right)}{\left(\frac{1}{x^2}\r  ight)\left(2\right)\left(\frac{1}{y^4}\right)}
    To learn the rules for exponents, try here. To learn how to simplify expressions such as the above, try here.

    To get you started:

    . . . . . \frac{\left(\frac{10}{x^2}\right)\left(\frac{y^3}{  1}\right)\left(\frac{1}{5}\right)\left(\frac{1}{y^  1}\right)}{\left(\frac{1}{x^2}\right)\left(\frac{2  }{1}\right)\left(\frac{1}{y^4}\right)}\,  =\, \frac{\left(\frac{10\times y^3\times 1 \times 1}{x^2\times 1\times 5\times y}\right)}{\left(\frac{1\times 2\times 1}{x^2 \times 1\times y^4}\right)}\, =\,  \left(\frac{10y^3}{5x^2 y}\right)\, \times\, \left(\frac{x^2 y^4}{2}\right)

    \mbox{2) Combine into one term: }\, \log(20b^3)\, -\,\log(5^2 b^2)\, +\, log(35)\, -\, log(28)
    To learn what the rules are and how to use them, try here.

    To get you started:

    . . . . . \log(20b^3)\, -\,\log(5^2 b^2)\, +\, log(35)\, -\, log(28)

    . . . . . =\, \log(20b^3)\, +\, \log(35)\, -\, \left(\log(5^2 b^2)\, +\, \log(28)\right)

    . . . . . =\, \log\left(20b^3\, \times\, 35\right)\, -\, \log\left(5^2 b^2\, \times \, 28\right)

    \mbox{3) Given }\, P(x)\, =\, 5x^3\, -\,4x^2\, +\,2x \, -\, 1\, \mbox{ and }\, D(x)\, =\, x\, -\, 2,

    \mbox{find the product }\, \left(P(x)\right)\left(D(x)\right).
    To learn how to multiply polynomials, try here.

    Once you have learned the basic terms and techniques, please attempt the exercises. If you get stuck, you will then be able to reply with a clear listing of your work and reasoning so far, so we can "see" where you're stuck and then provide intelligent assistance.

    Thank you!
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  6. #6
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    Thanks a lot for the tips and the link, great side.
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