Originally Posted by
algebraisabeast If I am simplifing an expression in which I cannot factor I can use polynomial division, I can also use synethic division to get the same answer. I know that I can only use synethic division when I am dividing by a linear equation.
When I change the leading coefficient on the linear equation I found that I have to divide my numbers when I do synthetic division by that number, why does this have to happen
example using poly division
(42x^2-33)/(7x+7) = 6x-6+9/7x+7
using synthetic I get 42x-42 with a remainder of 9
so I can say that r= 9/x+1 Is the reason that I divide by 7 because I take that out a 7 and use -1 so I have to put the 7 back in so I have to divide everything by 7 to get the same answer when I use poly division?
If I am using synthetic division to solve my answer will I always divide my two numbers by the leading cooefficient on my linear term.
Hi algebraisabeast,
Your polynomial long division answer is correct:
Now, when you attempt to use synthetic division and the coefficient of x is not 1, then you must divide everything by that coefficient, the divisor and the dividend.
Dividing everything by 7 you would have
Now set up your synthetic division process. Your divisor is now -1.
Code:
-1 | 6 0 -33/7
-6 6
-------------
6 -6 9/7
Above translates to which further simplifies to
Originally Posted by
algebraisabeast like if I want to divide 2x^2-17x-38 by 2x+3 if I use synthetic I will just divide by 2 when I am done
50k^3+10k^2-35k-7 divided by 5k-4 when I do synthetic divide all terms by 5?
This is correct. Now try one of those and see if you can do it.