Multiply or divide, write each answer in lowest terms.

3x^3-5x-2

------------

x-2

times

x-3

----

x+1

Where do i begin?

(corrected, format looked odd before)

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- Apr 7th 2009, 10:26 PMTenskypooLowest terms
Multiply or divide, write each answer in lowest terms.

3x^3-5x-2

------------

x-2

times

x-3

----

x+1

Where do i begin?

(corrected, format looked odd before) - Apr 7th 2009, 10:52 PMJhevon
- Apr 7th 2009, 11:02 PMTenskypoo
after doing

$\displaystyle 3x^2 - 5x - 2$

i came up with

$\displaystyle ( 3x + 1) ( x - 2)$

which eliminates the x-2 from the bottom of the other problem, leaving me with 3x+1? - Apr 7th 2009, 11:20 PMJhevon
- Apr 7th 2009, 11:25 PMTenskypoo
well i have to multiply $\displaystyle 3x + 1 $

by x-3 over x+1, how do i do that?

i want to GUESS. a heavy guess. that you rule out x+1 and you're left with x-3 over 3, or vise versa. - Apr 7th 2009, 11:44 PMJhevon
- Apr 7th 2009, 11:50 PMTenskypoo
I don't want to seem like a complete idiot, but could you possibly show me what the final set up before multiplying should be?

- Apr 8th 2009, 12:16 AMJhevon
$\displaystyle \frac {3x^2 - 5x - 2}{x - 2} \times \frac {x - 3}{x + 1} = \frac {(3x + 1)(x - 2)}{(x - 2)} \times \frac {x - 3}{x + 1} = (3x + 1) \times \frac {x - 3}{x + 1} = \frac {(3x + 1)(x - 3)}{x + 1}$