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Originally Posted by Tenskypoo based on your previous questions, it makes me feel this should be ...is that right?
yup. I've gotten to where it is (x+27)(x^2 - (x times 27))+ 27^2 __________________________________ x-3
Originally Posted by Tenskypoo yup. I've gotten to where it is (x+27)(x^2 - (x times 27))+ 27^2 __________________________________ x-3 nope ok, so if it is on top. you would write that as and apply the (difference of two cubes) formula:
Last edited by Jhevon; Apr 7th 2009 at 10:35 PM.
ah, because 3 x 3 x 3= 27 So if it was, x^4 - 16 it would be x^4 - 2^4 just as an example to see if i understand.
Originally Posted by Tenskypoo ah, because 3 x 3 x 3= 27 So if it was, x^4 - 16 it would be x^4 - 2^4 just as an example to see if i understand. ah, yeah, you could write it like that. but the formula i gave does not apply to that expression. but yes, that's the idea
Originally Posted by Jhevon nope ok, so if it is on top. you would write that as and apply the (difference of two cubes) formula: so would it be x^3 - 3^3 = (x - 3)(x^2 + (x times 3) + 3^2)
Originally Posted by Tenskypoo so would it be x^3 - 3^3 = (x - 3)(x^2 + (x times 3) + 3^2) yes, that's the numerator
i'd put that over x-3, but cancel out the x-3 since it is in both the numer. and denom. therefore leaving me with i may have done the part wrong, or it isn't simplified enough
Originally Posted by Tenskypoo i'd put that over x-3, but cancel out the x-3 since it is in both the numer. and denom. therefore leaving me with i may have done the part wrong, or it isn't simplified enough that is fine
Originally Posted by Tenskypoo yup. I've gotten to where it is (x+27)(x^2 - (x times 27))+ 27^2 __________________________________ x-3 Make sure you learn and memorize the formula for factoring a difference of cubes before the next test!
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