(x+27)(x^2 - (x times 27))+ 27^2
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x-3
nope
ok, so if it is $\displaystyle x^3 - 27$ on top. you would write that as $\displaystyle x^3 - 3^3$ and apply the (difference of two cubes) formula: $\displaystyle a^3 - b^3 = (a - b)(a^2 + ab + b^2)$
ok, so if it is $\displaystyle x^3 - 27$ on top. you would write that as $\displaystyle x^3 - 3^3$ and apply the (difference of two cubes) formula: $\displaystyle a^3 - b^3 = (a - b)(a^2 + ab + b^2)$