1. ## Fractions (Division)

Here is the problem:

Alex wants to sew bears. Each bear needs 1 and 2/3 yd fabric. She has 7 yd.How many can she make.

How I did it: 1 x 3 + 2 = 5/3

7/1 x 3/5 = 21/5
= 4 and 1/5

4 bears and 1/5 yard left.

The book says the correct answ. is 4 bears and 1/3 yard... how the heck do they get 1/3 and not 1/5?

2. Originally Posted by erj145aviator
Alex wants to sew bears. Each bear needs 1 and 2/3 yd fabric. She has 7 yd.How many can she make.

How I did it: 1 x 3 + 2 = 5/3

7/1 x 3/5 = 21/5
= 4 and 1/5

4 bears and 1/5 yard left.

The book says the correct answ. is 4 bears and 1/3 yard... how the heck do they get 1/3 and not 1/5?
I will guess that the last part of the exercise asked "and how much material will be left over?"

It often helps to keep track of units. The "7" is "seven yards", and the "5/3" is "five-thirds yards per bear". In dividing the yards by the yards-per-bear, you are finding "how many bears". The remainder, the 1/5, is one-fifth bear.

If one bear needs 5/3 yards of fabric, and the left-over fabric is enough to make one-fifth of a bear, then how many yards of fabric are left?

3. Thanks! How I managed to assume that was the left over material is beyond me.