it's

$\displaystyle 5^{x+1}=2(3^{2x})$

I have used base 10

and Im at x=log_5-log_2 over 2log_3-log_5/2

I expanded the bottom and cancelled -log_2

so I have log_5 over 2log3-log_5

I cant cancell the log base 5 because you cant make them have the same sign (neg. pos.) correct?

please help

thank you.