Thankful for help. Now I don't get how to write this. d+8 should be the numerator, d-2 the denominator. How do i get that?
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Hi First note that because the denominator must not be equal to 0 Multiply both sides by (d-2) d-2) = \frac94\d-2)" alt="\frac{d+8}{d-2} \d-2) = \frac94\d-2)" /> d-2)" alt="d+8 = \frac94\d-2)" /> Multiply both sides by 4 Spoiler: Expand both sides
Originally Posted by strunz Thankful for help. Now I don't get how to write this. d+8 should be the numerator, d-2 the denominator. How do i get that? There is a latex tutorial somewhere. You can type this problem as I have done below and click on someone's text to see what they typed. \frac{d+8}{d-2} = \frac{9}{4} Multiply both sides by (d-2) to give Then multiply by 4/5 to get your answer
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