Thread: The remainder and factor theorems

The remainder when x^2 - 3x + 1 is divided by (x + d) is 11. Find the possible values of d.

Originally Posted by Mr Rayon

The remainder when x^2 - 3x + 1 is divided by (x + d) is 11. Find the possible values of d.

Since the divisor is x + d, then the zero (when doing the synthetic division) is -d. So do the synthetic division:

Code:

-d | 1    -3         1
   |      -d    d^2+3d
   +------------------
     1  -d-3  d^2+3d+1

Set the remainder equal to the given value:

. . . . .

This rearranges as:

. . . . .

Either factor the quadratic and then solve the factors for the values of d, or else plug the above into the Quadratic Formula.

Hello, Mr Rayon!

The remainder when is divided by is 11.
Find the possible values of

From the heading, I assume you're expected to know the Remainder Theorem.

. . If a polynomial is divided by , the remainder is


We have: .

When is divided by , the remainder is


We have: . divided by

Hence: .

Therefore: .

Originally Posted by Soroban

Hence: .

...But what happened to the 11?

Originally Posted by Mr Rayon

...But what happened to the 11?

A small mistake by Soroban is what happened. But surely you can make the appropriate corrections .... Not that you need to do this, given Stapel's earlier post. Did you read it by the way?

Originally Posted by mr fantastic

A small mistake by Soroban is what happened. But surely you can make the appropriate corrections .... Not that you need to do this, given Stapel's earlier post. Did you read it by the way?

Yes...I never skip a post




d^2 + 3d - 10 = 0

Using the quadratic formula we get:

(-3 - 7)/2 = -5 or (-3 +7)/2 = 2

But are there any other ways to solve this apart from by factorising?

Originally Posted by Mr Rayon

But are there any other ways to solve this apart from by factorising?

Yes; you can solve the quadratic by using the Quadratic Formula, or you can complete the square.

Originally Posted by stapel

Yes; you can solve the quadratic by using the Quadratic Formula, or you can complete the square.

Yes...I tried to use completing the square but it got a bit messy down the end. I prefer using the quadratic formula.