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Thread: Is there a teacher in the house?

  1. #1
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    Is there a teacher in the house?

    If so if u have time can u check my work i think i got most of these problems right just wanted to check ur help will help me have a better life in the future


    2. Simplify and combine like terms:
    (1/4)(3x - 2) - (5/4)(2x - 6)
    (1/4)-(5/4)=(4/4)=1
    (3x 2)- -2x +6=
    5x -8


    3. Solve for x, collect variables on the left side of the equation:
    7x - 3 = - 5x 18
    7x + 5x =12x -5x +5x =0
    12x -3+3 =-18+3
    Divide 12 both sides 12/12x=-15/12
    X=-4/3 x=-1 1/3


    4. Solve for x, collect variables on the left side of the equation:
    4(x - 3) + 2 = 3x + 8 - 2x
    4x -12 +2 = 3x +8 -2x
    3x-2x=x -12 + 2=-10
    4x -10=x+8
    -x from both sides 3x -10=8
    Add 10 both sides 3x=18
    Divide 3 both sides x=6

    5. Solve for x, collect variables on the left side of the equation:
    (x 4)/2 1/4 = (6x - 1)/20
    Find LCD and simplify x -4 1/2 = 6x-1/10 add 1 to each side
    10 times all terms 10x 30 - 5 = 60x
    Minus 10x form both sides -25 = 50x
    Dived
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  2. #2
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    Quote Originally Posted by inthebegining View Post
    If so if u have time can u check my work i think i got most of these problems right just wanted to check ur help will help me have a better life in the future


    2. Simplify and combine like terms:
    (1/4)(3x - 2) - (5/4)(2x - 6)
    (1/4)-(5/4)=(4/4)=1
    (3x 2)- -2x +6=
    5x -8


    3. Solve for x, collect variables on the left side of the equation:
    7x - 3 = - 5x 18
    7x + 5x =12x -5x +5x =0
    12x -3+3 =-18+3
    Divide 12 both sides 12/12x=-15/12
    X=-4/3 x=-1 1/3


    4. Solve for x, collect variables on the left side of the equation:
    4(x - 3) + 2 = 3x + 8 - 2x
    4x -12 +2 = 3x +8 -2x
    3x-2x=x -12 + 2=-10
    4x -10=x+8
    -x from both sides 3x -10=8
    Add 10 both sides 3x=18
    Divide 3 both sides x=6

    5. Solve for x, collect variables on the left side of the equation:
    (x 4)/2 1/4 = (6x - 1)/20
    Find LCD and simplify x -4 1/2 = 6x-1/10 add 1 to each side
    10 times all terms 10x 30 - 5 = 60x
    Minus 10x form both sides -25 = 50x
    Dived
    2. $\displaystyle \frac{1}{4}(3x - 2) - \frac{5}{4}(2x - 6)$.

    You can only do the $\displaystyle \frac{1}{4} - \frac{5}{4}$ if you have a common factor. Here you don't.

    So you expand instead.

    $\displaystyle \frac{1}{4}(3x - 2) - \frac{5}{4}(2x - 6) = \frac{3}{4}x - \frac{1}{2} - \frac{5}{2}x + \frac{15}{2}$

    Now collect the like terms

    $\displaystyle = -\frac{7}{4}x + 7$.


    3. $\displaystyle 7x - 3 = -5x - 18$

    Collect all the x terms on one side and the constants on the other.

    $\displaystyle 7x + 5x = -18 + 3$

    $\displaystyle 12x = -15$

    $\displaystyle x = -\frac{15}{12}$

    $\displaystyle x = -\frac{5}{4}$.


    4. $\displaystyle 4(x - 3) + 2 = 3x + 8 - 2x$

    $\displaystyle 4x - 12 + 2 = x + 8$

    $\displaystyle 4x - 10 = x + 8$

    $\displaystyle 4x - x = 8 + 10$

    $\displaystyle 3x = 18$

    $\displaystyle x = 6$.


    5.$\displaystyle \frac{x - 4}{2} - \frac{1}{4} = \frac{6x - 1}{20}$

    We need to get rid of the denominators. Do this by multiplying both sides by 20 (since 2 and 4 are also factors of 20)

    $\displaystyle \frac{20(x - 4)}{2} - \frac{20}{4} = 6x - 1$

    $\displaystyle 10(x - 4) - 5 = 6x - 1$

    $\displaystyle 10x - 40 - 5 = 6x - 1$

    $\displaystyle 10x - 45 = 6x - 1$

    $\displaystyle 10x - 6x = -1 + 45$

    $\displaystyle 4x = 44$

    $\displaystyle x = 11$.
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