You can review this lesson, but a quick set-up might be:
. . . . .A + B = 2
. . . . .B = 2 - A
. . . . .(6/5)A - 2(2 - A) = 12
Then solve the linear equation.
Hi,
I'm trying to find the closed form of a second-order sequence. I'm down to the 'general solution' which is ( Un = A6/5^n + B(-2)^n ), but I'm having a simultaneous equation mind block.
Here's where I'm stuck:
U0 = 2 gives A + B = 2
U1 = 12 gives 6/5A - 2B = 12
Please can someone help to jog my memory on simultaneous equations, I'm staring blankly at these and Mathcad isn't helping.
Thanks.
You can review this lesson, but a quick set-up might be:
. . . . .A + B = 2
. . . . .B = 2 - A
. . . . .(6/5)A - 2(2 - A) = 12
Then solve the linear equation.
If you're not sure of your factoring, then multiply the factors back out and make sure you get what you'd started with.
(You should; the factorization is correct.)