How? What were your steps? (We can't find the errors until you

*show* your work.) (Wink)

By nature of

**geometric sequences**, yes, you need to set up the ratios. And since the ratio is "common", you get:

. . . . .$\displaystyle \frac{x\, +\, 12}{x\, +\, 3}\, =\, \frac{x\, +\, 3}{x\, -\, 1}$

Then you need to

**solve the rational equation**.

. . . . .$\displaystyle (x\, -\, 1)(x\, +\, 12)\, =\, (x\, +\, 3)(x\, +\, 3)$

. . . . .$\displaystyle x^2\, +\, 11x\, -\, 12\, =\, x^2\, +\, 6x\, +\, 9$

. . . . .$\displaystyle 11x\, -\, 12\, =\, 6x\, +\, 9$

I'm not seeing how you arrived at division by zero...? Please reply showing your steps in

**solving the linear equation**.

Thank you! :D