the horizontal distance is the distance between the starting point and the landing point of the javelin. Just solve the equation and you find two solutions. One can be ecarted because it is a negative one.
P.S: To solve a second degree use this:
Hey guys! I'm back with a question I am stuck on... thx for the help!
A javelin makes a parabola that follows the equation:
(distance in metres)
height = -1/25 (distance-15)^2 + 10
The first question was easy - find the starting height.
This occurs when d = 0, and you get 1 metre.
The second question; Find the turning point of the javelin = (15,10)
But the last question; what is the horizontal distance covered by the javelin has got me stumpted. It contains a square root sign somewhere in the answer I think, but I need some help.