Originally Posted by

**Beard** I'm stuck on b) iii) of this question. I'll show you what i have got so far.

the function f is given by f(x)= $\displaystyle \frac{9}{(1+2x)(4 - x)}$

a) express f(x) as a partial fraction.

I got $\displaystyle \frac{2}{(1+2x)} + \frac{1}{(4 -x)}$

b) i) Find the first three terms in the expansion of $\displaystyle \frac{1}{4 -x}$

I got $\displaystyle \frac{1}{4} + \frac{x}{16} + \frac{x^2}{64}$

b) ii) Obtain a similar expansion for $\displaystyle \frac{1}{1+2x}$

I got $\displaystyle 1 - 2x + 4x^2$

where i am stuck on is b) iii)

Hence, or otherwise, obtain the first three terms in the expansion of f(x) in ascending powers of x