solve 2(x-3)square -3 (x-1)square=3-(x+2) square
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Originally Posted by kwamamom solve 2(x-3)square -3 (x-1)square=3-(x+2) square recall that $\displaystyle (a \pm b)^2 = a^2 \pm 2ab + b^2$. So your equation becomes $\displaystyle 2(x^2 - 6x + 9) - 3(x^2 - 2x + 1) = 3 - (x^2 + 4x + 4)$ can you finish?
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