• Apr 2nd 2009, 10:38 AM
mj.alawami
Question

$\frac{25}{6}x^2=\frac{8}{3}$

Attempt
$75x^2-48=0$
• Apr 2nd 2009, 10:41 AM
e^(i*pi)
Quote:

Originally Posted by mj.alawami
Question

$\frac{25}{6}x^2=\frac{8}{3}$

Attempt
$75x^2-48=0$

Immediately the 6 and the 3 can be cancelled to 2 and 1 respectively:

$\frac{25}{2}x^2 = 8$

Take 8 from both sides:

$\frac{25}{2}x^2 - 8 =0$

Multiply through by 2 to clear the denominator:

$25x^2 -16 = 0$

Now you can use the difference of two squares to factorise
• Apr 2nd 2009, 10:42 AM
cnpranav