Solving quadratic equations by factorizing

Question

$\displaystyle \frac{25}{6}x^2=\frac{8}{3} $

Attempt

$\displaystyle 75x^2-48=0 $

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- Apr 2nd 2009, 10:38 AMmj.alawamiQuadratic Equations in one variable
**Solving quadratic equations by factorizing**

Question

$\displaystyle \frac{25}{6}x^2=\frac{8}{3} $

**Attempt**

$\displaystyle 75x^2-48=0 $ - Apr 2nd 2009, 10:41 AMe^(i*pi)
Immediately the 6 and the 3 can be cancelled to 2 and 1 respectively:

$\displaystyle \frac{25}{2}x^2 = 8$

Take 8 from both sides:

$\displaystyle \frac{25}{2}x^2 - 8 =0$

Multiply through by 2 to clear the denominator:

$\displaystyle 25x^2 -16 = 0$

Now you can use the difference of two squares to factorise - Apr 2nd 2009, 10:42 AMcnpranav
Is the answer +4/5,-4/5

- Apr 2nd 2009, 10:51 AMe^(i*pi)