Similarly, for . , not 0, so x- 2 must be a factor of . so b must be equal to 8.
You should also check that so that x- 4 also is a factor of
You could do that using a calculator. Or, for c, use the fact that if then and if then 3= 4^x[/tex]. Since 4 is larger than .4, it will take a smaller power to equal 3.In Q.28. is the c) part correct? If yes how?
When i is any number between 0 and 45, 90-i is between 45 and 90. tan(90-i)= cot(i)= 1/tan(i). So ln(tan(90-i))= ln(1/tan(i))= -ln(tan(i)). Every number i, for i between 0 and 45, is canceled by i between 45 and 90.In Q29. how is the d) part correct?
You can only do problems you have seen before? Surely not!In Q30. I don't know how to do this question at all never saw this question before. If anyone can explain this please surely do.
The shaded part is all points that are not in A and not in B. "not in A" means "in the complement of A" and "not in B" means "in the complement of B". Finally, "in X and in Y" is "in X intersect Y" so this is "complement of A intersect complement of B".
In Q32,33,34 How to do them also...
I know these are many questions but even if someone can solve any of them it would be really a great help .
I know they should be to their respective threads but it would have taken a lot of time so I apologize for that.