Three vessels having volumes in the ratio of 1:2:3 are full of a mixture of coke and soda.In the first vessel ratio of coke and soda is 2:3 , in the second 3:7, and in third 1:4.If the liquid in all the three vessels were mixed in a bigger container, then the resulting ratio of coke and soda is..
The answer is 4:11. But I am not getting how to get it.
Originally Posted by siddscool19
If we assume the first ship has a volume of VL then:
In ship one there will beof coke and so
of soda
In ship two there will beof coke and
of soda
In ship three there will beof coke and
Add the sum of the coke from the three ships and factor out V.
Add the sum of the soda from the three ships and factor out V
To find the ratio we divide the cola by the soda:
Now we have a ratio ofso we multiply by 11 to get an integer ratio of 4:11
(if you're having trouble visualising it try putting V=5)
The first vessel is coke:soda = 2:3, or five parts.
The second vessel is coke:soda = 3:7, or ten parts.
The third vessel is coke:soda = 1:4, or five parts.
Overall, their volumes are 1st:2nd:3rd = 1:2:3, but "5:10:5" doesn't match this. The first bit, the "5:10", matches the "1:2", but the second "5" doesn't match the "3". So make it match:
. . . . .third vessel: 3:12, or fifteen parts
Now you have:
The first vessel is coke:soda = 2:3, or five parts.
The second vessel is coke:soda = 3:7, or ten parts.
The third vessel is coke:soda = 3:12, or fifteen parts.
This gives you the right ratio, assuming all the "parts" are of the same volume, so the mixture will then be:
. . . . .fourth vessel: (2+3+3) : (3+7+12)
...or 8:22, which simplifies as 4:11.
  |
LinkBack URL
About LinkBacks