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  1. #1
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    help

    4x-5x>3x+2
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  2. #2
    MHF Contributor Quick's Avatar
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    Quote Originally Posted by jerryramos View Post
    4x-5x>3x+2
    Ask all your questions in one thread, it makes things neater...


    4x-5x>3x+2

    Subtract: -1x>3x+2

    Add 1x to both sides: 0>4x+2

    Subtract 2 from both sides: -2>4x

    Divide both sides by 4: \frac{-2}{4}>x
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  3. #3
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    Smile Solving inequalities ...

    Quote Originally Posted by jerryramos View Post
    4x-5x>3x+2
    <br /> <br />
4x-5x>3x+2<br />
    <br /> <br />
-x>3x+2<br />
    <br /> <br />
-2>3x+x<br />
    <br /> <br />
-2>4x<br />
    <br /> <br />
\frac{-2}{4}>x<br />
    <br /> <br />
\frac{-1}{2}>x<br /> <br />
    <br />
=> x<\frac{-1}{2}<br /> <br /> <br />


    Hope this helps


    Mahurshi Akilla
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  4. #4
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by mahurshi View Post
    <br /> <br />
4x-5x>3x+2<br />
    <br /> <br />
-x>3x+2<br />
    <br /> <br />
-2>3x+x<br />
    <br /> <br />
-2>4x<br />
    <br /> <br />
\frac{-2}{4}>x<br />
    <br /> <br />
\frac{-1}{2}>x<br /> <br />
    <br />
=> x<\frac{-1}{2}<br /> <br /> <br />


    Hope this helps


    Mahurshi Akilla
    How would this help? The question was asked 9 months ago and you didn't really change anything from what Quick posted?? (Except to add a few steps, which if the original poster didn't understand they would've posted their question by now...)

    -Dan
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  5. #5
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    Quote Originally Posted by topsquark View Post
    How would this help? The question was asked 9 months ago and you didn't really change anything from what Quick posted?? (Except to add a few steps, which if the original poster didn't understand they would've posted their question by now...)

    -Dan
    You're right. But I must say that the timestamps on these posts are too small to notice on the first glimpse.
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