A jet flies twice as fast as a propeller plane. On a trip 1500 miles, the propeller plane took 3 hours longer than the jet. Find the speed of each plane.
Hi Hapa,
Recall that 'Distance = Rate X Time'
d = rt
t =d/r
Let p = rate of prop plane
Let 2p = rate of jet plane
Let $\displaystyle \frac{1500}{p}$= time for the prop plane
Let $\displaystyle \frac{1500}{2p}$ = time for the jet plane
The distance is constant, and since the prop plane is 3 hours behind the jet plane, the two times wll equate this way:
$\displaystyle \frac{1500}{p}=\frac{1500}{2p}+3$
Multiply through by 2p
3000 = 1500 +6p
6p = 1500
p = 250 mph for the prop plane
The jet travels 500 mph