can i factor these completely? thanks for your time.
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Originally Posted by princess_21 can i factor these completely? thanks for your time. it didn't take me that long! now try to discover what i did!
Originally Posted by NonCommAlg it didn't take me that long! now try to discover what i did! i'm really stucked here, 1. then i got i don't know how to factor this
Originally Posted by princess_21 i'm really stucked here, 1. then i got i don't know how to factor this now use the identity:
oh, yes i got it. thank you very much! but how did you get the factor of ??
Originally Posted by princess_21 oh, yes i got it. thank you very much! but how did you get the factor of ?? Hi princess_21, Here's how this one breaks out: Factor out 2 in the 1st 3 terms: The grouped trinomial above can be factored: Now, to make things super simple, let u = (n-2). This factors into: Now, back substitute:
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