For the following 2 equations
1) x^3 - 1 = 0
and
2) x^3 + 1 = 0
to eork out do you just
1) x^3 = 1
x = 2sqr root 1??
and x^3 = -1
x = 2sqr root -1??
Thanks
$\displaystyle x^3 - 1 = 0
$
$\displaystyle (x-1)(x^2 + x + 1) = 0$
$\displaystyle x = 1$ , $\displaystyle x = \frac{-1 \pm i\sqrt{3}}{2}$
$\displaystyle x^3 + 1 = 0$
$\displaystyle (x+1)(x^2 - x + 1) = 0$
$\displaystyle x = -1$ , $\displaystyle x = \frac{1 \pm i\sqrt{3}}{2}$