8^-1 /y +3^-1 =-3
$\displaystyle \frac{8^{-1}}{y} + 3^{-1} = -3$
$\displaystyle \frac{1}{8y} + \frac{1}{3} = -3$
I'm going to clear the fractions: The least common multiple of 8y and 3 is 24y.
$\displaystyle 24y \left ( \frac{1}{8y} + \frac{1}{3} \right ) = 24y \cdot (-3)$
$\displaystyle 3 + 8y = -72y$
$\displaystyle 3 + 8y - 8y = -72y - 8y$
$\displaystyle 3 = -80y$
$\displaystyle y = - \frac{3}{80}$
-Dan