Solution :- Given y(S^4 + 3S^2 -12) = (104/s)+3 -24 +12S^3 - 3S^2 + 25S -15
s(S^4+3S^2-12)Y=104+s(12S^3-3S^2+25S-36)
because s(S^4+35^2-12)?0
Y=(12sS^3-3sS^2+25sS-36s+104)/s(S^4+3S^2-12)
hi
im trying to rearrange an equation to make y the subject to then use partial fraction expansion and laplace inverses to solve.
so far i have simplified to give
y(S^4 + 3S^2 -12) = 104/s+3 -24 +12S^3 - 3S^2 + 25S -15
i know i need to divide by the bracketed terms on the left but i dont know how to do this. i.e what is (104/s+3)/(S^4 + 3S^2 -12)
do i need a common denominator
any help would be appreciated
Please clarify the right hand side of yuor equation. What you wrote is this:
But I suspect what you meant is this:
Why didn't you combine the -24 and -15 terms?
One option is to multiply both sides through by (S+3), then divide both sides by the Y coeffeicient: