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Math Help - Help needed

  1. #1
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    Help needed

    Which is equivalent to:




    a. 6 + 6f = 24
    b. 6 + 6f = 12
    c. 2 + 3f = 12
    d. 6 + 3f = 12
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  2. #2
    A riddle wrapped in an enigma
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    Quote Originally Posted by henryW View Post
    Which is equivalent to:




    a. 6 + 6f = 24
    b. 6 + 6f = 12
    c. 2 + 3f = 12
    d. 6 + 3f = 12
    Hi henryW,

    I can't see your picture. I don't know if anyone else can either. Is there any way you can post what's in the picture?
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  3. #3
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    2/3 + f = 4
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  4. #4
    A riddle wrapped in an enigma
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    Quote Originally Posted by henryW View Post
    2/3 + f = 4
    Ok henryW,

    We need to get rid of the fraction by multiplying every term by 3.

    3(2/3) + 3f = 3(4)


    2 + 3f = 12

    I believe we have a match!
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