The question asks to solve

$\displaystyle log_a (3x + 4) - log_a x = 3 log_a 2 $

I have got to

$\displaystyle log_a \frac{3x + 4}{x} = log_a 8$

But I'm not sure if this is the correct method or what to do after this to solve it.

Could someone please help with this?