You are right
And the equation becomes
Solve for y and then find x
I have a problem that I am stuck on. I have been asked to solve the problem by finding all real solutions. The problem is: x^6-9x^3+8=0
I thought that I should use the ax^2+bx+c=0 but the 6th power is throwing me off.
If anyone could help, I would really appreciate it!
Hi! Thanks for the help!
The only question I have is- After doing the quadratic formula, is it possible to have to answers for "y"? And if I do have to answers (I have y=3 and y=-4) how do I plug that in for "x"?
Thanks again! Sorry if that is confusing!