. Setting s= 0 gives 8= 4A so A= 2. I presume that is what you have already done.
Although s= 0 is the only value that makes the equation that simple, any value of s give an equation.
If s= 1, 8= 5A+ 5B+ C+ D and you already know that A= 2: 5B+ C+ D= -2.
If s= -1, 8= 5A- 5B- C+ D so 5B+ C- D= 2.
Adding those two equations eliminates D immediately.
If s= 2, 8= 8A+ 16B+ 8C+ 4D so 16B+ 8C+ 4D= -8 or 4B+ 2C+ D= -2.
Adding that to 5B+ C+ D= -2 again eliminates D leaving two equations to solve for B and C.
Another method for problems like this is to combine like powers of s.
From , or, combining like powers, . For that to be true for all x, we must have coefficients of the same powers equal on both sides: B+ C= 0, A+ D= 0, 4B= 0, 4A= 8.
This method is often harder that just choosing value for s but here is much easier.