Originally Posted by

**rtblue** Well, for number 1:

$\displaystyle (3x-7)(x+5)$

Have you heard of something known as F.O.I.L? well, this stands for first, outer, inner, last. This is what you would use to solve a problem such as this. To start, you multiply both of the FIRST terms in the parenthesis, which are 3x and x. You will recieve $\displaystyle 3x^2$. next, you multiply the first and the OUTER (notice, the outer is the last one), these are 3x and 5. This is $\displaystyle 15x$. Then you multiply both of the INNER terms, which are -7 and x, and get $\displaystyle -7x$. Then you multiply both of the LAST(last in each of the parentheses) terms, which are -7 and 5 and get $\displaystyle -35$. After this, you combine like terms.