Help with some basic algebra

**jimmybob** · November 27th 2006, 10:03 AM

Need help with a few of these

Q1 Factorise this expression
bx + by +mx + my

Q2 make the symbol in brackets the subject

t = 2(pie) sq2 l
---
g

(pie) = pie symbol

sq2 = square root

Make l the subject

Q3. Same question again make the symbol in brackets the subject

p-mg = mv(sq)
------
r

Make M the subject

and (sq) is squared

Q4. Simplify the expressions

a(2) x a(3) x a(-5)

The number in brackets is the power

and square root 9a(4)b(2)

Thank you very much all!

**OReilly** · November 27th 2006, 10:15 AM

Originally Posted by jimmybob

Q1 Factorise this expression
bx + by +mx + my

$bx + by + mx + my = b(x + y) + m(x + y) = (x + y)(b + m)$

**OReilly** · November 27th 2006, 10:19 AM

Originally Posted by jimmybob

Q4. Simplify the expressions

a(2) x a(3) x a(-5)

The number in brackets is the power

and square root 9a(4)b(2)

Thank you very much all!

I think i saw this question before on this forum but I will answer it again.

$a^2 \cdot a^3 \cdot a^{ - 5} = a^5 \cdot \frac{1}{{a^5 }} = \frac{{a^5 }}{{a^5 }}1$

$\sqrt {9a^4 b^2 } = 3a^2 b$

**OReilly** · November 27th 2006, 10:24 AM

You posted Q4 again.

Previous your post where those questions are is:
http://www.mathhelpforum.com/math-he...l-subject.html

Don't double post.

**OReilly** · November 27th 2006, 10:28 AM

Originally Posted by jimmybob

Q3. Same question again make the symbol in brackets the subject

p-mg = mv(sq)
------
r

Make M the subject

and (sq) is squared

Do you mean to solve equation for m?

If it is then:

$\begin{array}{l} p - mg = \frac{{mv^2 }}{r} \\ \frac{{mv^2 }}{r} + mg = p \\ \frac{{mv^2 + rmg}}{r} = p \\ mv^2 + rmg = pr \\ m(v^2 + rg) = pr \\ m = \frac{{pr}}{{v^2 + rg}} \\ \end{array} $

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